3 ms·
For a 4096x4096 matrix its symmetry group has size 4096!. The Stirling’s approximation gives ln(4096!)=4096ln(4096)-4096 which is about 10~11 bits per 4096 numb
by renonce 2y ago
For a 4096x4096 matrix its symmetry group has size 4096!. The Stirling’s approximation gives ln(4096!)=4096ln(4096)-4096 which is about 10~11 bits per 4096 numbers. This is less than 0.003 bit per parameter saved.
- deleted 2y ago[deleted]