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“Standard” Thales proof (via two isosceles triangles) is simpler than this.
by akho 2y ago
“Standard” Thales proof (via two isosceles triangles) is simpler than this.
- lloeki 2y agoIt is, but Thales is what this article attempts to prove (a). By the point you've proven Thales with isosceles (b), proving that a parallelogram with equal diagonals is a rectangle thanks to Thales(b) in order to go forward along the Thales(a) proof is circular logic.