> However, if this is an order of magnitude difference , then it would push me to adopt the more-itertools formulation. My friend it's much worse than a single

> However, if this is an order of magnitude difference , then it would push me to adopt the more-itertools formulation. My friend it's much worse than a single order magnitude for small inputs import time import pandas as pd ls = list(range(10)) b = time.monotonic_ns() odds = [v for v in ls if v % 2] e = time.monotonic_ns() - b print(f"{e=}") bb = time.monotonic_ns() df = pd.DataFrame(ls) odds = df[df % 2 == 1] ee = time.monotonic_ns() - bb print(f"{ee=}") print("ratio", ee/e) >>> e=1166 >>> ee=656792 >>> ratio 563.2864493996569