4 ms·

I thought there was just a sign bit. If not, how does a system know if a number should be interpreted as positive or negative?

• dataflow 2y ago
  Signedness doesn't affect anything here, as long as the representation is in two's complement. The negation of x (i.e. -x) in two's complement is ~x + 1. The interpretation of the bits as signed or unsigned doesn't change any of the following steps.
  • MaxBarraclough 2y ago
    I think strictly speaking signedness does affect things, assuming we're talking C/C++. If x has type int and were to take the value of INT_MIN, then evaluating -x would result in a signed arithmetic overflow, which is undefined behaviour. (Related: the C standard now insists on use of 2's complement, where it used to permit other schemes.) If x had type unsigned int, this wouldn't introduce undefined behaviour.
• elevatedastalt 2y ago
  There's still a sign bit. The sign bit tells you whether to interpret the rest of the number as positive or treat as negative and undo the 2s complement operation.
• eslaught 2y ago
  You're thinking about a sign and magnitude representation, which is not how integers are represented in a modern computer. The modern version is two's complement. It still has a sign bit, but negating a number involves more than just changing the sign bit since the representation is modular. https://en.wikipedia.org/wiki/Two%27s_complement https://en.wikipedia.org/wiki/Two%27s_complement https://en.wikipedia.org/wiki/Modular_arithmetic https://en.wikipedia.org/wiki/Modular_arithmetic
  • gus_massa 2y ago
    I agree, but I just want to add that floating point numbers use sign and magnitude representation, so the GP may be confused by that.
• cvz 2y ago
  In the "two's complement" representation, there is a sign bit, but the meaning isn't "invert this number", it's "subtract a large, fixed power of 2 from this number". The reason this has become the most common representation for signed numbers in computer hardware is that it makes the difference between signed and unsigned numbers basically irrelevant as far as the hardware is concerned. When the difference does matter (which it does in division, conversions between different word sizes, conversions to/from text, and sometimes multiplication), there are two different instructions for signed and unsigned, and it's up to the programmer or compiler to pick the right one.
  • thaumasiotes 2y ago
    > n the "two's complement" representation, there is a sign bit, but the meaning isn't "invert this number", it's "subtract a large, fixed power of 2 from this number". This is only true if the size of your modulus is fixed. In fact, there is a "sign extension" command allowing you to produce, for example, signed 128-bit values from signed 64-bit values, and this basically requires interpreting two's complement values the same way they represent themselves: a three-bit -1 is just the sum of the positive values +1, +2, and +4. To extend that to six bits, you add the positive values +8, +16, and +32. The meaning of the high bit in our six-bit scheme shouldn't be viewed as "when this bit is set, subtract 32 from the value instead of adding it". It is "whether this bit is set or not, all higher bits in the number, the ones that don't exist in the hardware, are equal to it"; under this interpretation, the 8-, 16-, and 32- bits were already set in the three-bit value, and that's why they continue to be set when we do a sign extension. Every place value is still positive, but as long as there is no highest set bit, the number itself will be negative, and equal to the value you'd calculate from its representation as a geometric series.
    • kbolino 2y ago
      This is true mathematically but simple to implement in practice. If the number is signed, shifts to the right and widening casts fill the new bits with a copy of the sign bit. If it's unsigned, shifts to the right and widening casts fill the new bits with zeroes. Shifts to the left and narrowing casts work the same for signed and unsigned.
• pests 2y ago
  2s compliment helps with the problem of otherwise having a +0/-0 and lets you subtract numbers just with adders.
• School-Cotton 2y ago
  Assuming 4-byte integers, 0000 is 0 0001 is 1 0010 is 2 0011 is 3 0100 is 4 0101 is 5 0110 is 6 0111 is 7 1111 is -1 1110 is -2 1101 is -3 1100 is -4 1011 is -5 1010 is -6 1001 is -7 1000 is -8 The highest bit is always 1 when the sign is negative.
  • School-Cotton 2y ago
    Too late to edit, but I meant 4-bit, not 4-byte.
    • fuzztester 2y ago
      What is the edit window in hours?
  • jb1991 2y ago
    Useful example, thanks.