That should be probably resolved outside of the serialization. For example you can easily map -4n-1 to 2^(8+n), -4n-2 to 2^(8+n)-1, -4n-3 to 10^(3+n) and -4n-4

That should be probably resolved outside of the serialization. For example you can easily map -4n-1 to 2^(8+n), -4n-2 to 2^(8+n)-1, -4n-3 to 10^(3+n) and -4n-4 to 10^(3+n)-1 for all n >= 0.