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> but it doesn't cover every 'natural' way of generating coefficient vectors; But it covers one of the 'natural' ways. It seems like reasonable question to po
by scotty79 3y ago
> but it doesn't cover every 'natural' way of generating coefficient vectors;
But it covers one of the 'natural' ways. It seems like reasonable question to ponder.
- waldrews 3y agoOh yeah, definitely reasonable. I'm a statistician by trade, so if I see R^n, I want to put a multivariate normal measure on it, which means hyperspheres. Hypercubes are cool too. Just as long as we don't treat the limit from growing the hypercube to cover R^n as being equivalent to a uniform measure on R^n. Unlike, say, in probabilistic number theory, where they shamelessly get away with defining the equivalent of a uniform probability measure on infinitely many integers, much to the consternation of every other kind of mathematician.