4 ms·
Thank you, that's truly excellent! And although it is a little bit technical and more complex than the more standard proofs, it is exactly what it claims to be,
by WCSTombs 2y ago
Thank you, that's truly excellent! And although it is a little bit technical and more complex than the more standard proofs, it is exactly what it claims to be, a non-circular trigonometric proof of the Pythagorean Theorem. They use a key trigonometric identity sin(2*a) = 2*sin(a)*cos(a), which indeed is quite easy to prove without assuming the Pythagorean Theorem.