> it looks like you can just do it with ! in Haskell Yes, although it's slightly clumsy. example = do let suits = ["♠", "♥", "♦", "♣"] let num

> it looks like you can just do it with ! in Haskell Yes, although it's slightly clumsy. example = do let suits = ["♠", "♥", "♦", "♣"] let nums = concat [["A"], map show [2..10], ["J","Q","K"]] let cards = do pure (!nums ++ !suits) putStrLn (unwords (take 15 cards)) ghci> example A♠ A♥ A♦ A♣ 2♠ 2♥ 2♦ 2♣ 3♠ 3♥ 3♦ 3♣ 4♠ 4♥ 4♦