7 ms·
How do we know that that will converge to a single constant period of oscillation? Could you have a few different-sized square waves continue to cycle through t
by schoen 3y ago
How do we know that that will converge to a single constant period of oscillation? Could you have a few different-sized square waves continue to cycle through the circuit?
(I've never built or simulated that, I'm just trying to imagine what could happen!)
- rational_indian 3y ago>Could you have a few different-sized square waves continue to cycle through the circuit? No.
- schoen 3y agoCould you help improve my intuition about that, or give me a reference where I could learn more?
- rational_indian 3y agoFirst look up Barkhausen criteria, then read the following. For ring oscillators gain will be greater than unity for only those waves whose period matches the gate delay. Only one such wave exists since the gate delay is a fixed number.
- userbinator 3y agoIt is possible for a ring oscillator to generate harmonics: https://ieeexplore.ieee.org/iel5/16/31849/01482193.pdf https://ieeexplore.ieee.org/iel5/16/31849/01482193.pdf
- rational_indian 3y agoInteresting, would have loved to read the paper. Unfortunately I don't have an IEEE subscription right now.
- IncreasePosts 3y agohttps://sci-hub.ru/10.1109/T-ED.1982.20696 https://sci-hub.ru/10.1109/T-ED.1982.20696
- rational_indian 2y agoOkay, so I was wrong. You can get multiple harmonics if you use a long enough chain of inverters. I will simplify the paper mentioned in a sibling comment. In a long chain at any given point of time certain (variable number of) pairs of inverters drop in and out of the circuit changing the total propagation delay, giving rise to multiple harmonics. You'll have to read the paper for details.