4 ms·

The problem with new URL(), and how URL.parse() fixes that

3 points by kilian 2y ago

salil999 2y ago
In the example they have > const urlstring = "this is not a URL"; > const not_a_url = URL.canParse(urlstring) && new URL(urlstring); Why would you need the latter part of the condition? Couldn't it just be this? > const isValidURL = URL.canParse(urlstring);