2 ms·

Why? Is it mostly because of Haskell's purity (side-effect-freeness), so optimizations can change expressions more freely and safely?

• fooker 3y ago
  That, and the uniform s-expr/gadt representation of data structures instead of going wild with clever pointers.
  • dmytrish 3y ago
    I am not sure I understand what you mean in the context of Haskell.
    • fooker 3y ago
      https://wiki.haskell.org/GADTs_for_dummies https://wiki.haskell.org/GADTs_for_dummies