2 ms·
That's the chance of one specific person being hit. But I think you'd want to calculate the chance of any one person being "hit", which is roughly ten billion t
by xnorswap 3y ago
That's the chance of one specific person being hit. But I think you'd want to calculate the chance of any one person being "hit", which is roughly ten billion times higher than that, and uncomfortably likely (if people were actually 10m wide).
- ykonstant 3y ago>(if people were actually 10m wide). Apparently, we're working on that.