2 ms·
> This doesn't make 13 a power of two. Where did I imply that it is? > I'm aware of rejection sampling; my point was if you have a N bit value X and want M bi
by some_furry 3y ago
> This doesn't make 13 a power of two.
Where did I imply that it is?
> I'm aware of rejection sampling; my point was if you have a N bit value X and want M bits, truncating X to M bits and X MOD 2*M is the same.
Sure.
> Neither solve the problem where M > N, which is what TFA is about.
If you observe my other comments, you'll see I'm well aware of what the article is about.
- aidenn0 3y ago> Where did I imply that it is? You used 13 as an example in a response to my comment that was: Isn't modulo the same as truncation when dealing with powers of two?
- some_furry 3y ago> You used 13 as an example I don't see the number 13 in any of my comments on this thread (except this one, or where I quoted you). Perhaps you are confusing me with someone else?
- aidenn0 3y agoAh yes, that was lambdafu