4 ms·
Back in the day it was done via the unit circle. So the process goes something like this: 1. Define sin/cos as ratios in a triangle 2. Draw a unit circle with
by lrasinen 3y ago
Back in the day it was done via the unit circle. So the process goes something like this:
1. Define sin/cos as ratios in a triangle
2. Draw a unit circle with an appropriate triangle in the first quarter and note that for the vertex on the circle, x = cos alpha and y = sin alpha.
3. Assuming it holds for values of alpha > 90 deg, extend sin/cos definitions to match.
Don't quite remember how one got derivatives from that, because trig and calc were in separate modules. Possibly via the sum formula.