3 ms·
We don't know whether P = NP or not.
by JohnKemeny 3y ago
We don't know whether P = NP or not.
- jvanderbot 3y agoI realize that, but can you help me see why that's relevant here? The question as I understood it was BPP?=P, and I read that as "Do all problems that seem hard but have randomized algorithms actually live in P?" for which a counter example would be an NP-Hard problem with good randomized solution, right?
- bo1024 3y ago(Not who you asked, but) one important point here is definitely that BPP is about yes/no decision problems, and approximation algorithms are generally a different beast.
- jvanderbot 3y agoThat makes sense! Thanks I felt like I'm perpetually a beginner when it comes to computational complexity theory