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Yes, the lambda creates the function. Note that defvar does not. So there is still only one function being defined here.
by Tyr42 14y ago
Yes, the lambda creates the function. Note that defvar does not. So there is still only one function being defined here.
- anthonyb 14y agoOk, I see now. You've still got that &optional argument though. I don't see a huge amount of difference from a semantic point of view between that and the Python version though (ie. if x == None: ...).