3 ms·
> one basis could, for example, be two vectors pointing North and East; another could be a vector pointing along a certain road and one perpendicular to it. An
by OJFord 3y ago
> one basis could, for example, be two vectors pointing North and East; another could be a vector pointing along a certain road and one perpendicular to it.
And there's no requirement that they be perpendicular is there? The second just needs 'some amount of perpendicular', North and North-East for example? Since any [n, e] can also be described as [(1-sqrt(2)*e)*n, sqrt(2)*e] in the latter. (I think that's right, but my main point is you can do it, not the particular value there, and if that's way off I'll blame the fever.)
- Jensson 3y agoYou typically want an orthonormal basis though, but yes you don't need it.
- datascienced 3y agoIf you can walk this way / and this way | then you can do / minus | to get your orthogonal -
- OJFord 3y agoYes exactly.