4 ms·
Since you know JavaScript, this should help. Uncurried: ((x, y) => x * y)(3, 5) === 15 Curried: (x => y => x * y)(3)(5) === 15 If you don't understand that
by curry_is_easy 3y ago
Since you know JavaScript, this should help.
Uncurried:
((x, y) => x * y)(3, 5) === 15
Curried:
(x => y => x * y)(3)(5) === 15
If you don't understand that, your problem is that you don't understand anonymous functions (lambdas), not that you don't understand currying.