3 ms·
AFAIK one can also consider the 4D velocity vector to have a constant lenght. Thus the faster you move in the spatial dimensions, the slower you move in the tim
by magicalhippo 3y ago
AFAIK one can also consider the 4D velocity vector to have a constant lenght. Thus the faster you move in the spatial dimensions, the slower you move in the time dimension to maintain the constant length.
- bloopernova 3y agoThat's a helpful explanation, thank you.
- bumby 3y agoWhy must the velocity vector have a constant length?
- CydeWeys 3y agoNow that's the billion dollar question, isn't it. But it's true.
- numpad0 3y agoSo to preoccupy your mind with simulation hypothesis and inter-node bandwidth estimation for the cluster we’re on. edit: wait, if the Vector4.magnitude == 1, are dense objects actually just fast/hot?
- anticensor 3y agoWith constant magnitude vectors, you can eliminate one of the numbers out of the motion simulation for each particle. Huge optimisation indeed.
- magicalhippo 3y agoAs the sibling comment alludes to, it's otherwise they wouldn't behave according to what we measure. For a deeper "why", see Feynman[1]. edit: it's related to how spacetime with a finite speed of light is represented mathematically. There's some discussion here[2] which might shed some light. [1]: https://fs.blog/richard-feynman-on-why-questions/ https://fs.blog/richard-feynman-on-why-questions/ [2]: https://en.wikipedia.org/wiki/Imaginary_time#In_cosmology https://en.wikipedia.org/wiki/Imaginary_time#In_cosmology
- deleted 3y ago[deleted]