3 ms·
Just to be very clear, are you saying this paper looks good to you? You are not seeing any red flags? Like, for example, the fact that the 7th entry of Table 2
by credit_guy 3y ago
Just to be very clear, are you saying this paper looks good to you? You are not seeing any red flags?
Like, for example, the fact that the 7th entry of Table 2 contains 0% Uranium, but still has a K_eff of 1.095. What does that even mean?
Or like the following sentence on page 15:
> The MCNP6 modeling and calculation of the moderating ability of the fuel projectile that evaluated the uses of Lithium-6, Lithium-7, Boron-10, Boron-11, Carbon-12, and H2O
Why would you even consider Boron-10, which is one of the strongest neutron poisons? Maybe it's a mistake, right? Well, 3 of the rows in Table 1 contain Boron-10, and one (the ninth row) is the "champion" at the amount of energy production. A funny champion, considering that again it does not include any Uranium.
As for the iron not vaporizing, I suspect you are basing your conclusion on this statement:
> Because the projectile heats up so fast, there is no time for conductive heating of the iron. Since all the naturally occurring isotopes of iron have a thermal neutron absorption cross section less than 2.5 barns, direct neutron heating will not dominate. Therefore, it is highly probable that the iron sheath around the bullet will remain a solid far deeper into the barrel.
That "highly probably" is a bit vague. What exactly happens when the iron sheath disintegrates? Will it change phase instantaneously in its entirety, or from the inside to the outside. And if it's the second, will shrapnel hit the barrel? If It does, it's kind of a problem, isn't it?
> Power generation in the barrel is approximately 1/25th that in the projectile.
Does this mean that after firing 25 projectiles (i.e. after 25 seconds) the power generation in the barrel is equal to the power that is sufficient to vaporize the projectile? You could say it's not a biggie, because the barrel is much more massive, but it's finite. What happens after 250 seconds, or 2500 seconds? And more importantly, what happens to the neutron economy in the whole system after a good amount of the uranium in the barrel undergoes fission under this neutron bombardment? Are we going to have Xenon poisoning at some point?
I could go on, but you get the idea.