3 ms·
I think its bootless to try to define the "minimum possible" Kolmogorov complexity. Here's why: 1. Note, kolmogorov complexity is defined by the length of
by rhelz 3y ago
I think its bootless to try to define the "minimum possible" Kolmogorov complexity. Here's why:
1. Note, kolmogorov complexity is defined by the length of the shortest program which prints out the string. What counts is the number of instructions, and not the complexity of those instructions.
2. So say S is a very complex spring. We can always construct a turing machine which could print out S using a zero length program: it could just start in a state which prints out S when you turn it on, and then halts.
3. So there is no such thing as a turing machine which prints out every string shorter than any other turing machine prints it out, QED.
That's the bad news. The good news is we don't even need to do that. For any string S, say that M and N are any two universal turing machines. Without loss of generality, specify that KM(S) <= KN(S). Then there is always some C for which KM(S) <= KN(S) + C. The constant C being the length of the program required to emulate machine M on machine N.
We are used to abstracting out constant sums and constant factors like this. The strings we are dealing with (as a species) are growing in length exponentially--that's why we went from 8-bit, to 16bit, etc computers. So as the length of S goes to infinity, the difference between the its complexity for any two machines becomes negligible.