3 ms·
XNOR does not distribute over AND or any other binary operators (try 0 XNOR (0 AND 1)), nor does it have a multiplicative identity, so it's not really multiplic
by scarmig 3y ago
XNOR does not distribute over AND or any other binary operators (try 0 XNOR (0 AND 1)), nor does it have a multiplicative identity, so it's not really multiplication in a way that's useful.