3 ms·
If you use the made up averaging scheme of ((5^p+50^p)/2^p)^(1/p), 25 is the limit as p -> inf (i think). ...Because it just simplifies to 50/2 lol.
by winwang 3y ago
If you use the made up averaging scheme of ((5^p+50^p)/2^p)^(1/p), 25 is the limit as p -> inf (i think).
...Because it just simplifies to 50/2 lol.