3 ms·
No need for a nested array. You can simply lay them end to end in decreasing size and perform in-place merges. The structure is implicit in the size of the se
by colanderman 3y ago
No need for a nested array. You can simply lay them end to end in decreasing size and perform in-place merges. The structure is implicit in the size of the set.
- keybored 3y agoOkay, I was looking at the Rust implementation (nested Vec).