5 ms·
Isn't it just errors_count/7? (errors_count * 1/7) For example, if you got 70 errors before you now get only 10 errors.
by zigzag312 3y ago
Isn't it just errors_count/7? (errors_count * 1/7)
For example, if you got 70 errors before you now get only 10 errors.
- musiciangames 3y ago7 times 70 =490. 490 fewer than 70 is -420. But words mean what you want them to mean, so 7 times fewer to mean 1/7th is becoming commonplace. (edited because formatting swallowed asterisk for times)
- zigzag312 3y agoIs there any case where your interpretation makes sense? Would you ever say 0.86 times fewer instead of 0.86 of the size? If new is 1/7 the size of the old, then 7 * new = old. It takes 7 times of new_count to get the value of old_count. 1/7th of the old_count. 7x fewer seems like a shorthand, but I'm not a native English speaker. x times != x times fewer 7 times => multiply 7 times fewer => multiply by fraction
- musiciangames 3y agoI would never say times fewer, because it is ambiguous.
- zigzag312 3y agoWhen value is above 1, it's not really ambiguous anymore as only one interpretation makes sense. But I understand that it could still be incorrect, if it's not well defined term in English.
- musiciangames 3y agoYou choose an interesting case at 1. What does 1 times less errors mean? To me it means no errors.
- zigzag312 3y agoIt's ambiguous as it's not above or below 1 :)
- djbusby 3y agoGotta put a back-whack in like \* for *