3 ms·
a^2 = 1, first base vector is a regular one b^2 = -1, second base vector is "imaginary" ab = 0, base vectors are orthogonal (a+b)^2 = a^2 + 2ab + b^2 = 1
by thesz 3y ago
a^2 = 1, first base vector is a regular one
b^2 = -1, second base vector is "imaginary"
ab = 0, base vectors are orthogonal
(a+b)^2 = a^2 + 2ab + b^2 = 1 + 2\*0 + (-1) = 0
Trick is taken from conformal geometric algebra [1].
[1] https://en.wikipedia.org/wiki/Conformal_geometric_algebra https://en.wikipedia.org/wiki/Conformal_geometric_algebra