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One very interesting thing about automatic differentiation is that you can think of it as involving a new algebra, similar to the complex numbers, where we adjo
by MikeBattaglia 3y ago
One very interesting thing about automatic differentiation is that you can think of it as involving a new algebra, similar to the complex numbers, where we adjoin an extra element to the reals to form a plane. This new algebra is called the ring of "dual numbers." The difference is that instead of adding a new element "i" with i² = -1, we add one called "h" with h² = 0!
Every element in the dual numbers is of the form a + bh, and in fact the entire ring can be turned into a totally ordered ring in a very natural way: simply declare h < r for any real r > 0. In essence, we are saying h is an infinitesimal - so small that its square is 0. So we have a non-Archimedean ring with infinitesimals - the smallest such ring extending the real numbers.
Why is this so important? Well, if you have some function f which can be extended to the dual number plane - which many can, similar to the complex plane - we have
f(x+h) = f(x) + f'(x)h
Which is little more than restating the usual definition of the derivative: f'(x) = (f(x+h) - f(x))/h
For instance, suppose we have f(x) = 2x² - 3x + 1, then
f(x+h) = 2(x+h)² - 3(x+h) + 1
= 2(x² + 2xh + h²) - 3(x+h) + 1
= (2x² - 3x + 1) + (4x - 3)h
Where the last step just involves rearranging terms and canceling out the h² = 0 term. Note that the expression for the derivative we get, (4x-3), is correct, and magically computed itself straight from the properties of the algebra.
In short, just like creating i² = -1 revolutionized algebra, setting h² = 0 revolutionizes calculus. Most autodiff packages (such as Pytorch) use something not much more advanced than this, although there are optimizations to speed it up (e.g. reverse mode diff).
- compacct27 3y agoWhere do I go to learn what you just said?
- smokel 3y agoThe book referred to in this post has some information about this. The method with "dual numbers" is called "forward-mode automatic differentiation". PyTorch seems to use "reverse-mode automatic differentiation", which does not use dual numbers, but keeps track of the computation graph.
- fpgamlirfanboy 3y agoyou guys are wrong and spreading blatant misinformation - there is no magic number whose square is 0 but which is itself not zero anywhere in pytorch or tensorflow or any other real DNN framework that i'm familiar with. it's all fun and games to participate in math woo but you shouldn't be proclaiming things you don't actually know on a public forum.
- drdeca 3y agoI don't know why you keep calling it "magic". Whether or not pytorch uses them, they aren't magic, neither in the derogatory sense nor in the praise sense.
- fpgamlirfanboy 3y ago> I don't know why you keep calling it "magic". because they have all of the gee-whiz factor of a freshman calc proof of the chain rule that divides and multiplies infinitesmals and absolutely not enough of the substance necessary to prove much more than that. they are absolutely, in the research literature, at best an anachronism (harkening back to leibniz) and at worst a parlor trick. in literally my first response i provided the most trivial counter-example to the magic of non-standard analysis. no answers (crickets). i surmise this is because the people in here talking it up aren't really serious.
- drdeca 3y agoAs I use the terms, the dual numbers are a different thing from non-standard analysis. Non-standard analysis, as I understand the term, uses non-standard models of the real numbers, and its infinitesimals do not satisfy h^2 = 0. In non-standard analysis, f'(x) is the standard part of (f(x+h)-f(x))/h , for an infinitesimal h (i.e. for a non-standard real which is smaller than any non-zero standard rational number). (In order to apply this definition, f should be defined in a way which does not use anything requiring determining if a number is standard, or taking the standard part of something, etc.) The dual numbers, on the other hand, are the ring R[h]/(h^2) . This is not a field, while non-standard models of the real numbers do form fields. The dual numbers suffice to define differentiation of polynomials (which may not be sufficient for some purposes! [a]), and something like dual numbers is used in algebraic geometry to define the Zariski tangent spaces for points of algebraic varieties (whether in characteristic 0 or in characteristic p. In characteristic p, one certainly can't use an epsilon-delta definition!). I really don't see your point about the "gee-whiz factor". While different things, both non-standard analysis and dual numbers can be handled rigorously, and have their use-cases, even though I certainly would at least default to thinking of differentiation in terms of the limits definition (assuming I'm thinking of any specific definition at all). I assume that the counter-example you refer to is the (dx/dy)(dy/dz)(dz/dx) thing. That indeed doesn't seem like the kind of thing that using the dual numbers would be especially suited for. Though, also, not the sort of thing that should really come up in auto-diff I would think? If there is a common parameterization of the values of x,y,z by some variable t (on some interval I), on some neighborhood of the point under consideration, where {(x(t),y(t)) | t in I}, {(y(t),z(t)) | t in I}, and {(z(t),x(t)) | t in I}, are each differentiable functions, and where they satisfy the relationships between the variables x,y,z from the larger context, and all three of (dx/dy), (dy/dz), (dz/dx) exist at the point in question, then it seems that the product should be 1. [a] Though, if the function is analytic (not just smooth), unless I'm missing something, it should also give the right answer (but still not a good definition of course, because should define differentiation before defining what it is for a function to be analytic.) (of course, just because the function is analytic doesn't make its domain include the dual numbers. One has to take a power series for it, and apply this power series to the element of the ring of dual numbers, not apply the original function to it.)
- MikeBattaglia 3y agoThere are a few good resources. Here is a good blog post with some introduction: https://towardsdatascience.com/forward-mode-automatic-differentiation-dual-numbers-8f47351064bf https://towardsdatascience.com/forward-mode-automatic-differ... Some thorough notes from MIT: https://book.sciml.ai/notes/08-Forward-Mode_Automatic_Differentiation_(AD)_via_High_Dimensional_Algebras/ https://book.sciml.ai/notes/08-Forward-Mode_Automatic_Differ... Here is a teacher who taught a class using these, calling the dual element dx instead of h: https://cornellmath.wordpress.com/2007/08/28/non-nonstandard-calculus-i/ https://cornellmath.wordpress.com/2007/08/28/non-nonstandard...
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- fpgamlirfanboy 3y ago> Most autodiff packages (such as Pytorch) use something not much more advanced than this pytorch absolutely does not use the dual number formulation - there are absolutely no magic epsilons anywhere in pytorch's (or tensorflow's) code base. what you're calling duals are the adjoints where are indeed stored/cached on every node in pytorch graphs. there's a reason no one uses dual numbers (non-standard analysis) for anything (neither autodiff nor calculus itself): because manipulating infinitesmals like this is fraught formal manipulation (it's algebra...) where as limits are much more rigorous (bounds, inequalities, convergence, etc.). my favorite question to ask the non-standard analysis n00bs is: please tell me under what conditions this is true (dx/dy)(dy/dz)(dz/dx) = 1 edit: anyone that thinks i'm wrong and this other guy is right should go and do some reading, eg where this guy tried to make this same point and got shot down: https://math.stackexchange.com/a/341550 https://math.stackexchange.com/a/341550 spoiler alert: there's a reason you had to learn epsilon-delta proofs and limits and it's not because your math professors are mean. this is why i hate this kind of "TIL, gee whiz" math tidbits - they're full of exclamation marks and fancy sounding words ("non-archimedean rings" oooo fancy) but almost always come from a wikipedia level understanding, not actual research.
- MikeBattaglia 3y agoAt the end of the day, if you are storing inputs and outputs to a function as a pair of numbers - one for the actual value, and one for the derivative - and if addition and multiplication work the way you expect and propagate derivatives correctly - then you are using dual numbers, regardless of if you notate it a + b*h or {"value": a, "derivative": b}. Pytorch does things slightly differently in that it is mostly focused on reverse-mode autodiff, and so it stores adjoints relative to the overall output rather than partial derivatives relative to the input, but this isn't really an entirely different thing, in the same way that the FFT isn't entirely different from the DFT. There seems to be some confusion about the relationship between dual numbers and smooth infinitesimal analysis. Both have nilpotent elements, but with dual numbers the background logic is classical, whereas it isn't with smooth infinitesimal analysis. EDIT: I see you've edited your post to try to get in some extra criticism after I've already responded. That's terrible form, so I'll just respond here. Dual numbers are a nice way to get started with forward-mode autodiff, to which it is so related that the two are essentially the same thing with different labels. Pytorch instead uses reverse-mode autodiff. Reverse-mode and forward-mode autodiff are different, but not so different that they are entirely different things. Reverse-mode is, as I put it in my OP, "not much more advanced" than forward-mode, even if not identical. What is entirely different, much more advanced, and what Pytorch really doesn't do, is anything like the "epsilon-delta proofs" you keep hanging your hat on. If Pytorch did that, it would be useless. The entire point of autodiff is to avoid such things. Beyond that, I would suggest slowing down a bit as you are mixing quite a few things up. Nonstandard analysis has nothing to do with dual numbers at all, for instance. And you're very much misinterpreting that MSE post of mine you linked to (thanks!).
- clooper 3y agoYour are confusing non-standard and dual numbers. The dual numbers are not ordered and contain non-invertible nilpotent elements such as h which squares to 0.
- MikeBattaglia 3y agoThese things are different and I did mean dual numbers. The dual numbers do form an ordered ring. When you complain about certain elements being non-invertible, I think you are probably complaining that they aren't a field.
- clooper 3y agoIf a < b then a^2 < b^2. This is not true if you let a = 0 and b = h. The dual numbers do not have an ordering. You should provide sources and proofs next time because it seems like you are just making things up.
- MikeBattaglia 3y agoThat isn't what an ordered ring is. Your property of a < b → a² < b² doesn't even hold true in the integers. For instance, let a = -2 and b = -1. The correct property is that if a ≤ b, a + c ≤ b + c, and if a ≥ 0 and b ≥ 0, then ab ≥ 0. It is fairly easy to see that these properties hold for dual numbers.
- clooper 3y agoIn my argument a and b are positive and this is true for all ordered rings but not for the dual numbers as you've defined them. Specify the ordering and you will realize h can not be larger nor smaller than 0 because both cases lead to a contradiction. In any case, I'm dropping out of this thread.
- MikeBattaglia 3y agoIt isn't true for all ordered rings, and the dual numbers are in fact a counterexample to the claim that it is true. Beyond that I'm not sure what to tell you, other than it's fairly easy to see that the dual numbers do satisfy the axioms of an ordered ring that I gave. Here's a large survey of various infinitesimal systems by Philip Ehrlich where he also notes the dual numbers are an ordered ring: https://arxiv.org/pdf/1808.03345.pdf https://arxiv.org/pdf/1808.03345.pdf.
- kristjansson 3y agoDual numbers implement forward mode automatic differentiation, but is there additional value to viewing AD in terms of duals e.g. when we’re implementing reverse mode (backprop)?
- naasking 3y agoDepends what you mean by "additional value". Dual numbers are very simple, and enough for reverse mode AD too though, even via a purely functional implementation: Provably Correct, Asymptotically Efficient, Higher-Order Reverse-Mode Automatic Differentiation, https://dl.acm.org/doi/pdf/10.1145/3498710 https://dl.acm.org/doi/pdf/10.1145/3498710
- MikeBattaglia 3y agoThis is a good question that doesn't have a short answer. There are some different philosophical opinions about this. One way to look at this is to note that even with forward mode autodiff, there have generally historically been two different viewpoints for the whole thing, which I'll call the "computer science" view and the "algebraic" view. The computer science view involves things that look computational graphs with nodes that look like {"value": 123, "deriv": 456}. We are storing real values along with propagated partial derivatives. We have a custom * operator which sets a * b = {"value": a.value * b.value, "deriv": a.value * b.deriv + b.value * a.deriv}. Other functions, like exp, sin, cos, log, etc are also extended to handle these kinds of input. There's a ton of literature that views things using this kind of framework going back to the 1960s. The algebraic view uses dual numbers. Instead of writing {"value": 123, "deriv": 456}, we write 123 + 456h. We get the same results as the above: (a + bh) * (c + dh) = ac + (ad + bc)h. We can extend many functions in a natural way to the dual plane, such as exp, sin, cos, log, and get values there. There's also plenty of literature on these, going back to the late 1800s. A modern view is to note that these two things are *identical*. It isn't that forward mode autodiff "uses" dual numbers; it is dual numbers. The set of elements of the form {"value": x, "deriv": y}, with addition and multiplication as stated, satisfies the axioms of a real algebra and is isomorphic to the dual numbers. We could have written {"real_part": x, "dual_part": y} if we wanted. You can see this viewpoint in some of the links I've posted elsewhere here.^[1] So given all of that background, there are two answers to your original question. The first is to just simply view it as that "reverse-mode autodiff doesn't use dual numbers." Many people have this view, and I would say that that it really focuses on what I've called the "computer science" view above. The second view is to note that the relationship between reverse-mode autodiff and dual numbers is the same as the relationship between reverse-mode autodiff and forward-mode autodiff. It would be silly to say that they are totally different, unrelated things: at the end of the day all we are really doing is changing the order in which we perform a bunch of multiplies of Jacobian matrices. I tend to view it as similar to the relationship between the DFT and the FFT: there is this super elegant linear algebra view involving DFT matrices. Do we say that the FFT "doesn't use matrices?" Well, I guess, but are we going to go so far as to say that it also doesn't involve linear algebra, etc? That is my view. There are a few other differences between reverse-mode and forward-mode autodiff. Each individual operation in the computation graph, for instance, can be thought of as an individual instance of forward-mode autodiff. In reverse-mode, on the other hand, we typically store the (back-)propagated adjoints as additional data on the input node objects, not the output nodes. This is useful if we are thinking of backpropagation on a graph. It's up to you if you view these as involving materially different theories or just differences of implementation for the sake of optimization. In short, the main thing is that there's less literature on a purely algebraic version of reverse-mode autodiff in general. [1] There is one important difference: we often think of the dual numbers as an ordered ring with "h" infinitesimal. The first viewpoint doesn't use this part of the mathematical structure - and it's very interesting to note that it isn't even necessary! Although it's cute to think of h as infinitesimal, the autodiff properties we get flow purely from the algebraic properties of having h^2 = 0, regardless of order. Of course, though, we can always just think of the dual numbers as an unordered ring, if we want.
- noqc 3y agoNilpotents aren't exactly new.