4 ms·
Calculation time! Key assumptions. Wookiepedia lists 120 km for the diameter of the first Death Star [1]. Density of steel is around 8000 kg/m^3 [2]. As a w
by ooterness 3y ago
Calculation time!
Key assumptions. Wookiepedia lists 120 km for the diameter of the first Death Star [1]. Density of steel is around 8000 kg/m^3 [2]. As a wild guess, I'll assume a uniform sphere with about 1/4 that density (i.e., rho = 2000 kg/m^3), to account for open space etc.
Surface gravity [3] is given by g = (4pi/3) * G * rho * r = 0.03 m/s^2
(i.e., about 0.3% that of Earth).
Escape velocity [4] is given by v = sqrt(2 * g * r) = 60 m/s = 134 mph
This is faster than I would have guessed, but I would expect that to be in reach for a good trebuchet. It's reasonable to assume the compactor is required to load compressed trash into such a device.
[1] https://starwars.fandom.com/wiki/Death_Star/Legends https://starwars.fandom.com/wiki/Death_Star/Legends
[2] https://en.wikipedia.org/wiki/Steel#Properties https://en.wikipedia.org/wiki/Steel#Properties
[3] https://en.wikipedia.org/wiki/Surface_gravity#Relationship_of_surface_gravity_to_mass_and_radius https://en.wikipedia.org/wiki/Surface_gravity#Relationship_o...
[4] https://en.wikipedia.org/wiki/Escape_velocity#Calculation https://en.wikipedia.org/wiki/Escape_velocity#Calculation
- op00to 3y agoDo you think whatever artificial means they use to create gravity on the Death Star would affect the escape velocity?