3 ms·
Why is the matrix diagonalizable with an eigendecomposition of that form?
by enthdegree 3y ago
Why is the matrix diagonalizable with an eigendecomposition of that form?
- nicf 3y agoThis is the Spectral Theorem. It says (in the version for real matrices, which are what we have here) that any symmetric matrix has an orthonormal basis of eigenvectors, or equivalently that any symmetric matrix can be diagonalized via an orthogonal change of coordinates.