4 ms·
Since the dataset is small enough so that it fits into the Linux kernel page cache, and since the benchmark is repeated for 5 consecutive times, first iteration
by menaerus 3y ago
Since the dataset is small enough so that it fits into the Linux kernel page cache, and since the benchmark is repeated for 5 consecutive times, first iteration of the benchmark will be bottlenecked by the disk I/O but the remaining 4 will not - e.g. all data will be in RAM (page-cache).