3 ms·
The fib' function (the more efficient version of fib) is defined using f. So the goal is to prove that f computes the same thing as fib (given the appropriate a
by mayoff 3y ago
The fib' function (the more efficient version of fib) is defined using f. So the goal is to prove that f computes the same thing as fib (given the appropriate arguments to f and fib). Hence the theorem needs to use f on at least one side of the equation.