3 ms·
But is it accelerating or just increasing at a constant rate? The second derivative of the graph looks like ~0 to me. We need to reduce the rate to 0 (or be
by bryanlarsen 3y ago
But is it accelerating or just increasing at a constant rate? The second derivative of the graph looks like ~0 to me. We need to reduce the rate to 0 (or below) which means deceleration.