>And yes, in a perfectly circular orbit there would be no overshoot?? That's where you and the other comment are wrong. The only way to get a stable circular t

>And yes, in a perfectly circular orbit there would be no overshoot?? That's where you and the other comment are wrong. The only way to get a stable circular two body orbit is for newtonian potentials which are exactly 1/r shaped. Add any other term (like 1/r^3 for General Relativity) and you essentially get more or less chaotic movement over time, similar to the three body problem in newtonian gravity. See Betrand's theorem [1]. [1] https://en.wikipedia.org/wiki/Bertrand%27s_theorem https://en.wikipedia.org/wiki/Bertrand%27s_theorem