4 ms·
What? 13*28=364 So, missing ~1.25 days every year (instead of ~0.25 days each year with a 365 day calendar). How does this solve leap years?
by foolswisdom 3y ago
What?
13*28=364
So, missing ~1.25 days every year (instead of ~0.25 days each year with a 365 day calendar). How does this solve leap years?
- roland35 3y ago1 or 2 "year day" holidays at the end of the calendar which aren't part of any month
- dave4420 3y agoAnd this is supposed to be simpler?
- thfuran 3y agoI propose that we just extend "year day" to cover the entire year and leave only a single month called Null. This solves not only leap days but also leap seconds and even timezones: The time in year day isn't part of any month, day, hour, or minute so there's no problem.
- deleted 3y ago[deleted]