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No, I can see that. It's the same as the logical OR operator | computing unions of sets. I just fail to see how this solution is better than a standard paramete
by agubelu 3y ago
No, I can see that. It's the same as the logical OR operator | computing unions of sets. I just fail to see how this solution is better than a standard parameterized query, it feels much more opaque without any obvious upsides.