But if you have an incorrect key, you'll always execute the whole for loop & one write to `isMatch`. I'm assuming the function would take the same amount of ti

But if you have an incorrect key, you'll always execute the whole for loop & one write to `isMatch`. I'm assuming the function would take the same amount of time to run regardless for which value of "i" the write occurs at. Wouldn't that then protect the attack vector of enumerating keys and checking the time? As in, the only input that would cause the write to `isMatch` to be skipped would be the correct key, in which case you don't need to brute force the solution.