2 ms·
yes, you are correct. s = "foo\nbar\nbaz" # 'foo\nbar\nbaz' len(s) # 11 j = json.dumps(s) # '"foo\\nbar\\nbaz"' # \n is escaped as \\n len(j) #
by jgalt212 3y ago
yes, you are correct.
s = "foo\nbar\nbaz"
# 'foo\nbar\nbaz'
len(s) # 11
j = json.dumps(s)
# '"foo\\nbar\\nbaz"'
# \n is escaped as \\n
len(j) # 15