I know, which is why I'm hoping that's not the case. But then, if that's not the case for /proc/<other>/fd/<n>, why would it be for /proc/self/fd/<n> ? Where d

I know, which is why I'm hoping that's not the case. But then, if that's not the case for /proc/<other>/fd/<n>, why would it be for /proc/self/fd/<n> ? Where does this expectation come from?