6 ms·
It's not even always the optimal strategy playing prisoner's dilemma. If all your opponents are playing "always defect", playing Tit-for-tat will consistently l
by _Algernon_ 3y ago
It's not even always the optimal strategy playing prisoner's dilemma. If all your opponents are playing "always defect", playing Tit-for-tat will consistently lose (because of the initial good-faith attempt at cooperation).
- knightoffaith 3y agoRight - if I recall, the story is that there were computer-simulated tournaments in which different strategies for playing the iterated prisoner's dilemma were pitted against each other, and tit-for-tat is the strategy that emerged to be the winner. So it's an empirical result showing that it is generally the most successful strategy, not mathematically shown to be optimal against every strategy.
- deleted 3y ago[deleted]