4 ms·
Surely you don't need the phone's actual latitude and longitude. I can't imagine that the direction to a point infinitely (basically) far away will be different
by RobotCaleb 3y ago
Surely you don't need the phone's actual latitude and longitude. I can't imagine that the direction to a point infinitely (basically) far away will be different depending on where on this tiny planet you're standing. I'm sure just using the Earth's position (or any other position in our solar system?) would be sufficient to get a valid pointing vector.
- thrance 3y agoI think you still need to know where the phone is located on Earth to compute the normal vector (i.e. where is up ?)
- swyx 3y agoexactly this. GP hasn't internalized what it means to have a non-geocentric mental model of the galaxy. we are but a speck on an arm on a not-particularly significant little cluster of fireballs
- quickthrower2 3y agoAn analogy would be the centre circle of a soccer field. Walk around it but always face outwards. Now as you do that point to a city 100 miles away. Insignificant circle but…
- genmon 3y agoThat's it exactly. You need the lat/long, time+date, and device orientation in order to float the arrow