4 ms·
Not a mathematician, but if there's a computable limit, then why not? E.g. most integers aren't powers of 2, cause lim(n to inf: n / 2^n) = 0
by wruza 3y ago
Not a mathematician, but if there's a computable limit, then why not? E.g. most integers aren't powers of 2, cause lim(n to inf: n / 2^n) = 0