3 ms·
You are upgrading the number type to string when you are doing the eq operation and from string to number when doing ==. https://perldoc.perl.org/perlnumber ht
by petre 3y ago
You are upgrading the number type to string when you are doing the eq operation and from string to number when doing ==.
https://perldoc.perl.org/perlnumber https://perldoc.perl.org/perlnumber