3 ms·
rd = rs1 * rs2 + rs3 It's no different from parsing if/then/else. Provided one assignment maps to one opcode, it's unambiguous.
by _a_a_a_ 3y ago
rd = rs1 * rs2 + rs3
It's no different from parsing if/then/else. Provided one assignment maps to one opcode, it's unambiguous.