4 ms·
Off the top of my head and using my fingers the probability is: 4901:4900 in favor of red. (100*98/2 = 100*49. Plus one in favor of red) If the number of dist
by thsksbd 3y ago
Off the top of my head and using my fingers the probability is:
4901:4900 in favor of red. (100*98/2 = 100*49. Plus one in favor of red)
If the number of distribution were odd, the odds would be even.
Am I right?
- friend_and_foe 3y agoWhere did you get 98 from? Let's try it as a set of 3 balls. You have 3 balls in an urn, random number of red v green, the first one you pull is red, what's the likelihood that the second one you pull is also red?
- thsksbd 3y agoThose are the distributions that perfectly mirror. There is another one that is alone that has an extra ball, 50:49. So I added one to one side instead of 50 and 49 to the other. So 4950:4949. ... is that right? Im pretty sure red is favored, and Im pretty sure if the number of dists were odd the odds would be even. But are the odds right?