3 ms·
No, that's not right. Do those first four steps. You wouldn't (necessarily) cover every black point in your rectangle. Choose a remaining black point and flood
by neilkk 3y ago
No, that's not right.
Do those first four steps. You wouldn't (necessarily) cover every black point in your rectangle. Choose a remaining black point and flood fill from that, say green. Keep on doing this with different colours until you've covered every black point in your rectangle. You have a bunch of regions of different colours.
Now, if the different coloured regions are all nicely separate, then your set is locally connected. Because each point is either cleanly in one component or cleanly in the other.
If on the other hand your drawing looks like https://commons.m.wikimedia.org/wiki/File:Julia_set_for_the_rational_function.png https://commons.m.wikimedia.org/wiki/File:Julia_set_for_the_... with mixed up boundaries where some points are infinitesimally close to more than one colour, then it's not locally connected.
The difficulty with intuition is that in our intuition, coloured regions always have reasonable boundaries (think countries in a map: the border can be wiggly but there's never infinitely many tiny bits of one country mixed up in the boundary of two others). In fractal geometry, things like the Newton fractal picture above are quite usual.
- hermitcrab 3y agoI think I understand now. Much appreciated! 'Locally connected' seems like quite poor terminology.