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Zig is trying to replace C, not C++ You can imagine someone will make Zig++ or something like it one day. But I think it’s best to get a foundation with a 100%
by audunw 3y ago
Zig is trying to replace C, not C++
You can imagine someone will make Zig++ or something like it one day. But I think it’s best to get a foundation with a 100% explicit, and as simple as possible a language.
There’s a bunch of features like RAII and operator overloading and such that people may rightly feel is necessary. But that’s not for a C replacement.