4 ms·
> With three phones and a one-in-eight chance of being affected (assuming 50% for each phone) 1/8 would be the chance to have all 3 affected. The chance of hav
by leto_ii 3y ago
> With three phones and a one-in-eight chance of being affected (assuming 50% for each phone)
1/8 would be the chance to have all 3 affected. The chance of having at least one affected would be 1-1/8.
- jacquesm 3y agoCorrect, I meant to write 'unaffected'. I'll fix it, thank you.