3 ms·
the part you're missing is that during the acceleration phase, if the 1 way speed of light is different, the velocities achieved relative to a stationary observ
by adgjlsfhk1 3y ago
the part you're missing is that during the acceleration phase, if the 1 way speed of light is different, the velocities achieved relative to a stationary observer by accelerating for t seconds relative to the clock that is doing the acceleration will be different depending on the direction of acceleration.
- AnimalMuppet 3y agoTo what order in v? I'd like to see your math, but I'm pretty sure I can still minimize that by going slow (relative to the speed of light in any direction).
- adgjlsfhk1 3y agoWikipedia does the math for us here. https://en.wikipedia.org/wiki/One-way_speed_of_light#Slow_clock-transport https://en.wikipedia.org/wiki/One-way_speed_of_light#Slow_cl.... The TLDR is that the standard lorentz transform assumes the 1 way speed of light doesn't vary, so to do the math correctly you need generalized lorentz transformations https://en.wikipedia.org/wiki/One-way_speed_of_light#Generalizations_of_Lorentz_transformations_with_anisotropic_one-way_speeds https://en.wikipedia.org/wiki/One-way_speed_of_light#General...