2 ms·
OK, so that diagram was intended to be horizontal, not vertical. Obviously you want to minimize vertical movement as much as possible. But I see what you mean
by AnimalMuppet 3y ago
OK, so that diagram was intended to be horizontal, not vertical. Obviously you want to minimize vertical movement as much as possible.
But I see what you mean about the sides (as drawn) being parallel.
And, yes, I meant isotropic, not anisotropic. Embarrassing.
OK, how about this: I have an equilateral triangle, with vertices A, B, and C. I synchronize clocks four clocks at A. I send one clock to B directly, and one to C and then B. I send one clock to C directly, and one to B and then C. I do the same from points B and C. Then, I can look at the difference between clocks that came direct and clocks that came the long way. If all the differences are the same, then I can say that going A-to-B-to-C has the same effect as going A-to-C-to-B or B-to-A-to-C or any other route. Doesn't that show isotropy?
- lmm 3y ago> Then, I can look at the difference between clocks that came direct and clocks that came the long way. If all the differences are the same, then I can say that going A-to-B-to-C has the same effect as going A-to-C-to-B or B-to-A-to-C or any other route. Doesn't that show isotropy? Again, no, because you can only measure around the full loop. Any clock you can compare has gone just as far east as it has gone west, just as far north as south, and just as far up as down. You can rule out some particular kinds of anisotropy, but there are possible patterns that just wouldn't show up.