3 ms·
That problem can be solved with estimation of the roots on a number line. It's not the most precise way of calculating it but when visualized you can clearly se
by crq-yml 3y ago
That problem can be solved with estimation of the roots on a number line. It's not the most precise way of calculating it but when visualized you can clearly see that the root of 13 will have a fractional part above .5, while the root of 2 will have a fraction below .5.
- lupire 3y agoDid you actually solve it? 5 times <1.5 is <7.5, and 2 times >3.5 = >7 so "more or less than .5" is insufficient for this comparison.
- lupire 3y agoYou can solve it, however, by knowing that 5√2 < 5 * 1.45 = 7.2 (either because √2 = 1.414... is well known, or 1.45^2 = 2.125 is easy because 1.45^2 = 1.41.5 + .0025) 2√13 > 2√12.96 = 2 * 3.6 = 7.2 (36^2 = 6^4 = 1296 is a common fact from dice probability.) P.S: 0.45^2 = .2025 and 1.45 = 2.125 is an amusing coincidence.